Filtering arrays in JavaScript

Using filter() in JavaScript can be really handy, you can filter an array in so many ways, lets explore a little bit about that.

Numbers

Start with a simple numbers array:

const array = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

Now, lets filter this array in order to return only values below 8:

const array = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

// We're *saying*, get me all values
// that are less less (<) than 8
array.filter((value) => value < 8)

With this filter it'll return [1, 2, 3, 4, 5, 6, 7], pretty neat right?

Lets try a few more examples before moving on. Check the comments on the code:

const array = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

// Get only odd numbers
array.filter((value) => value & 1) // [1, 3, 5, 7, 9]

// Get only even numbers
array.filter((value) => !(value & 1)) // [2, 4, 6, 8, 10]

// Get values between `3` and `8`
array.filter((value) => value > 3 && value < 8) // [4, 5, 6, 7]

As you can see we can use filter() in many ways, lets play a little bit with strings 🙂

Strings

Again, lets set up a simple array:

const array = ['@telmo', 'https://telmo.im', 'Fullstack Developer']

Lets assume we want to filter just URLs, so, we can filter strings that start with http as an example:

const array = ['@telmo', 'https://telmo.im', 'Fullstack Developer']

array.filter((value) => value.startsWith('http'))

This will return ["https://telmo.im"]. I love JavaScript!

Since we know handlers start with an @, we can do exactly the same thing to filter all handlers, lets add a few more entries into our array:

const array = ['Telmo', '@telmo', '@codinghubio', 'Coding Hub']

array.filter((value) => value.startsWith('@'))

This should return ["@telmo", "@codinghubio"], sweet!

Objects

Finally, lets just go through a more complex array, an array of objects, lets assume an array of profiles:

const profiles = [
  { name: 'Telmo', handler: '@telmo', followers: 1000 },
  { name: 'Catalin', handler: '@catalinmpit', followers: 2000 },
  { name: 'Marc', handler: '@_marcba', followers: 3000 },
]

Now lets try and filter profiles that have more than 1000 followers:

profiles.filter((value) => value.followers > 1000)

With this filter you should get:

[
  {
    "name": "Catalin",
    "handler": "@catalinmpit",
    "followers": 2000
  },
  {
    "name": "Marc",
    "handler": "@_marcba",
    "followers": 3000
  }
]

In the filter you can do another thing, which is destructuring the followers directly, like this:

profiles.filter(({ followers }) => followers > 1000)

I was about to end this writing now, but... We can still use another approach into how we filter arrays.

Lets assume we have an array with numbers and strings, and we want to filter the array to return just the strings, how do we check in JavaScript if something is a string?

typeof something === 'string'

Right, lets take the following example:

const array = [1, 3, 'Telmo', 4, 6, '@telmo']

// We can use the `typeof` directly in the filter
array.filter((value) => typeof value === 'string')

It should return ["Telmo", "@telmo"], awesome! But, we can refactor this a little bit, assume you might want to use a function that checks if something is a string, lets take a look:

const array = [1, 3, 'Telmo', 4, 6, '@telmo']

function isString(value) {
  return typeof value === 'string'
}

array.filter(isString)

This returns exactly the same ["Telmo", "@telmo"], but look how our filter() got much cleaner, and bonus, you can re-use the isString() function somewhere else.

Note that this is not a right way of doing things approach, you should use whatever you think is fits you best.

That's it, hope it helped somehow ✌️